Looking back on high school stuff, I crossed 1 easy looking problem that I can't solve
here it is
if ax+b=3 and a cannot equal 0, then x= ?
2007-09-04 05:20:29 · 9 answers · asked by rocker chick 2 in Science & Mathematics ➔ Mathematics
ax = 3 - b
x = (3 - b) / a
2007-09-07 21:31:52 · answer #1 · answered by Como 7 · 1⤊ 0⤋
here,
ax + b = 3 a cannot equal 0,
then,
x=(3 - b)/a.
here a != 0 means value of x is finite
2007-09-04 05:25:33 · answer #2 · answered by Sunny P 2 · 0⤊ 0⤋
Solve for x thusly:
ax + b = 3
ax = 3 - b
x = (3 - b)/a, provided a isn't 0. (if a is 0 then x has no value)
2007-09-04 05:26:28 · answer #3 · answered by TurtleFromQuebec 5 · 0⤊ 0⤋
ax + b = 3
x = (3 - b)/a
Yes, the function is not defined at a = 0.
2007-09-04 05:24:42 · answer #4 · answered by gebobs 6 · 0⤊ 0⤋
ax + b = 3
ax = 3 - b
x = (3 - b)/a
Now values or a and b are need to calculate the value of x.
2007-09-04 05:28:04 · answer #5 · answered by Sparks 6 · 0⤊ 0⤋
ax + b = 3
therefore, x
= (3 - b)/a
2007-09-04 05:25:10 · answer #6 · answered by Bananaman 5 · 0⤊ 0⤋
ax+b=3
thus, x = (3-b)/a
Simple, or is it a trick question?
2007-09-04 05:25:24 · answer #7 · answered by palindrome 2 · 0⤊ 0⤋
You would still have to know the value of b.
2007-09-04 05:36:34 · answer #8 · answered by the handyman 2 · 0⤊ 1⤋
x=(3-b)/a
b and a could be any value you want.
2007-09-04 05:26:56 · answer #9 · answered by Rancio 2 · 0⤊ 0⤋