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Vector A has a magnitude of 12.0 m
Vector B has a magnitude of 18.0 m
Here is the figure(just copy and paste it to your address box):

http://i60.photobucket.com/albums/h23/cjantono/gg.jpg

2007-09-04 04:28:31 · 2 answers · asked by tata 2 in Science & Mathematics Mathematics

2 answers

Well graphically you construct a parallelogram, and a vector drawn from the origin to the the point opposite on the parallelogram, will be the resultant vector.

You can also solve this by deriving the x and y components using geometry and adding the values together.

2007-09-04 04:34:32 · answer #1 · answered by Brian K² 6 · 0 0

One of the vectors is at an angle to the x-axis. Drop a perendicular line from the tip of the vector to the x-axis. Or use the trigonometric formula:

X-component of B = B.cos 37 since the angle is given as 37 degrees.

Now subtract the Bx from A and if the magnitude is +ve, show it on the right side of the origin on x-axis and if the magnitude is -ve, show it on the left side of the origin on the x-axis.

I am assuming that A is -ve and B is +ve.

OK. I verified and Bx (the x-component of B) is more than A.

Magnitude of Bx - A = 2.375...

Similarly do the vertical component of B ( vertical component of A will be zero). Then reconstruct the vector by drawing the y-component and the x-component and join the origin with the point of intersection of the x- and y- components.

2007-09-04 11:43:23 · answer #2 · answered by Swamy 7 · 0 0

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