a squard - b squard + 2bc - c squard
2007-09-04 04:13:57 · 9 answers · asked by Benita A 1 in Science & Mathematics ➔ Mathematics
a^2-b^2+2bc-c^2
=a^2-(b^2-2bc+c^2)
=(a)^2-(b-c)^2
=(a+b-c)(a-b+c)
2007-09-04 04:28:19 · answer #1 · answered by Anonymous · 1⤊ 0⤋
a ² - b ² + 2 b c - c ²
a ² - (b ² - 2 b c + c ²)
a ² - (b - c) ²
( a - (b - c) ) (a + (b - c) )
( a - b + c ) ( a + b - c )
2007-09-07 05:53:59 · answer #2 · answered by Como 7 · 2⤊ 0⤋
There are 2 ways to factorise this.
Step 1
From the equation: a^2-b^2=(a+b)(a-b)
We will get (a+b)(a-b) + c(2b-c) Taking out c as a common factor too.
Step 2
From the equation a^2 - 2ab + b^2 = (a-b)^2
We will get a^2 -(b^2 -2bc + c^2) = a^2 -( b-c)^2
= (a+b-c)(a-b+c)
Step 2 factorises further so its the better method.
2007-09-04 11:31:34 · answer #3 · answered by nothingtodo007 2 · 0⤊ 1⤋
a^2 - b^2 + 2bc - c^2
= a^2 - (b^2 - 2bc + c^2)
= a^2 - (b-c)^2
= [a-(b-c)][a+(b-c)]
= (a-b+c)(a+b-c)
2007-09-07 18:39:51 · answer #4 · answered by Kemmy 6 · 0⤊ 0⤋
a^2 - b^2 - c^2 + 2bc
a^2- ( b^2 + c^2 - 2bc)
Since (b-c)^2 = b^2 + c^2 - 2bc so
a^2 - (b - c)^2
Hope it helps.
2007-09-04 11:24:38 · answer #5 · answered by bunny rabbit 2 · 0⤊ 1⤋
What bunny rabbit said is right, but stops short:
a^2 - (b - c)^2
This is the classic different of two squares, so that expression can be factored as...
(a + (b-c)) (a - (b-c))
Getting rid of the parenthesis gives the final answer:
(a + b -c) (a - b + c)
2007-09-04 11:30:29 · answer #6 · answered by ryanker1 4 · 1⤊ 0⤋
a^2 - b^2 - c^2 + 2bc
= a^2 - ( b^2 + c^2 - 2bc)
= a^2 - (b - c)^2
=[a-(b-c)][a+(b-c)]
=(a-b+c)(a+b-c)
2007-09-04 11:29:26 · answer #7 · answered by cllau74 4 · 0⤊ 1⤋
(a^2-b^2)+(2bc-c^2)=(a-b)(a+b)+c(2b-c)
2007-09-04 12:37:10 · answer #8 · answered by nikki 2 · 0⤊ 1⤋
(a+b-c)(a-b+c)
2007-09-04 11:27:42 · answer #9 · answered by Peter T 2 · 0⤊ 1⤋