2007-09-04 04:08:19 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
f ( g (x) )
= f (2 x + 1)
= 1 - (2 x + 1) ²
= 1 - (4 x ² + 4 x + 1)
= - 4 x ² - 4 x
= (- 4 x) ( x + 1 )
2007-09-07 21:16:49 · answer #1 · answered by Como 7 · 0⤊ 1⤋
u just replace all the x's in f(x) = 1 - x^2
with 2x + 1 from g(x)
f(g(x))= 1 - (2x+1)^2
2007-09-04 11:13:18 · answer #2 · answered by Anonymous · 0⤊ 1⤋
f(g(x)) = (sqrt (2x+1 (1-x^2)) = x^2 -3x +1 = 14
2007-09-04 11:13:03 · answer #3 · answered by Anonymous · 0⤊ 1⤋
f[g(x)] = f(2x+1)
= 1-(2x-1)^2
= 1-(4x^2-4x+1)
= -4x^2 +4x
2007-09-04 11:17:09 · answer #4 · answered by New football fan 1 · 0⤊ 1⤋
f(g(x)) = 1 - (g(x)) ^ 2
= 1- (2x + 1) ^ 2
= 1 - (4x^2 + 4x + 1)
= -4x^2 - 4x
2007-09-04 11:14:41 · answer #5 · answered by Aaron 2 · 0⤊ 1⤋
g(x) = 2x + 1
f(x) = 1 - x^2
f(g(x)) = 1 - (2x+1)^2
= 1 - (4x^2 + 4x + 1)
= 1 - 4x^2 - 4x - 1
= -(4x^2 + 4x)
2007-09-04 11:12:54 · answer #6 · answered by gudspeling 7 · 0⤊ 1⤋
g(x)= 2x+1
so f(2x+1)=1-(2x+1)^2
so f(g(x))= 1-(2x+1) (2x+1)
put them together and you have 1- (4x^2+4x+1)
so then subtract 1
so you are left with f(g(x))= 4x^2+4x as your final answer
functions are hard.
2007-09-04 11:19:17 · answer #7 · answered by computer whiz 5 · 0⤊ 1⤋
First of all put value of x in g(x) e.g. x=1 implies that g(x)=3
Now put this value in f(g(x)) i.e. f(3) which will be 1-(3^2)
Simplem ain;t it!
2007-09-04 11:17:07 · answer #8 · answered by Coming Soon, near You! 1 · 0⤊ 1⤋
f(g(x))=f(2x+1)
f(g(x))= 1-(2x+1)^2
f(g(x))= 1-4x^2-4x-1
f(g(x))= -4x^2 -4x
2007-09-04 11:21:59 · answer #9 · answered by Patric E 1 · 0⤊ 1⤋