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2007-09-04 03:32:09 · 11 answers · asked by Benita A 1 in Science & Mathematics Mathematics

11 answers

a - 2a b + 2 b - 1
a (1 - 2 b) - (1 - 2 b)
(1 - 2 b) (a - 1)

2007-09-07 21:12:27 · answer #1 · answered by Como 7 · 0 0

a + 2b - 1 - 2ab

Notice 2b is a factor of two of the terms :
2b - 2ab = 2b(1 - a)

We already have a - 1 in the original expression,
so to make the above factorisation the same,
just multiply 2b by -1 and (1 - a) by -1.
Then you get : 2b(1 - a) = -2b(a - 1).

Now the whole expression is : a - 1 - 2b(a - 1)
and we have a - 1 in two terms, so take it out as a factor.
= (a - 1)(1 - 2b) which is the final answer.

2007-09-04 03:43:50 · answer #2 · answered by falzoon 7 · 0 0

look at the coefficients.
in front of a and -1 you have the coefficient 1
in front of 2b and -2ab you have the coefficient 2

try grouping that way first.

notice that 2b-2ab has a common factor of not just 2 but 2b
2b-2ab=2b(1-a)

a+2b-1-2ab = a-1 +2b-2ab = a-1 + 2b(1-a)
a-1 + 2b(1-a) = -1(1-a) + 2b(1-a)
-1(1-a) + 2b(1-a) = (1-a)(2b-1)

2007-09-04 03:50:54 · answer #3 · answered by trogwolf 3 · 0 0

assume, a=1;b=1
solve, a+2b-1--2ab
solu,
a+2b-1--2ab=1+2(1)-1-2(1)(1)
=1+2-1-2
=3-3
a+2b-1--2ab =0.

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frm,
A.ARAVIND RAJ
mail id- namalu_242@yahoo.co.in

2007-09-04 05:39:54 · answer #4 · answered by A.ARAVIND R 1 · 0 0

rearrange this...
a - 1 - 2ab + 2b
= 1 ( a - 1 ) - 2b ( a - 1 )
= (1 - 2b ) ( a - 1 )
hope u get it

2007-09-04 03:40:33 · answer #5 · answered by PRIYADARSHINII 2 · 0 0

that's an expression, no longer an equation. there are techniques on a thank you to element via finding the GCF of the expression. The GCF can contain variables, yet on no account decimals or fractions. we locate the GCF of the two words. discover out all the values. the excellent form of the 1st term is one million and the 2d is two, so there can't be an entire variety interior the GCF. The a of the 1st term is squared and of the 2d that's raised to the 1st power. a (no longer a^2) is interior the GCF. The b of the 1st term is raised to the 1st power and likewise of the 2d term that's. b is interior the GCF. The GCF must be ab. Divide ab from each term. a^2b/ab = a 2ab/ab = 2 upload those values, positioned them in parentheses, and multiply the GCF ab. that's the factorization. ab(a + 2)

2016-10-09 22:31:53 · answer #6 · answered by Anonymous · 0 0

a+2b+1-2ab=

(2b-2ab) +(a+1)=
-2b(-1+a) +(a+1)=
-2b(a+1) +(a+1)=
(a+1)(-2b+1)

2007-09-04 04:14:02 · answer #7 · answered by Patric E 1 · 0 0

a+2b-1-2ab = a-1+2b-2ab
=a-1-2b(a-1)
=(a-1)(1-2b)

2007-09-04 04:04:31 · answer #8 · answered by kilua 1 · 1 0

a + 2b - 1 - 2ab
a + 2b(1 - a) - 1
a - 1 + 2b(1 - a)
a - 1 - 2b(a - 1)
(a - 1)(1 - 2b) -- The Answer

2007-09-04 09:04:46 · answer #9 · answered by lenpol7 7 · 0 0

a+2b-1-2ab
= a-2ab+2b-1
= a(1-2b)-1(-2b+1)
= a(1-2b)-1(1-2b)
=(a-1)(1-2b)

2007-09-04 03:36:19 · answer #10 · answered by Anonymous · 1 0

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