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you may assume that lim x-->o ((sinx)/(x))=1

2007-09-04 03:26:49 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

[x→0]lim 72 tan x/sin x
[x→0]lim 72 (sin x/cos x)/sin x
[x→0]lim 72/cos x
72/cos 0
72

2007-09-04 03:35:14 · answer #1 · answered by Pascal 7 · 0 0

((72tanx)/(sinx))

= ( (72(sinx/cosx)) / (sinx) )

= (72/cosx)



lim x->0 (72/cosx) = 72 / 1

= 72

2007-09-04 03:40:19 · answer #2 · answered by Aaron 2 · 0 0

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