As the moon passes over a point on the earth surface, the water is drawn up by gravitational pull, which explains why one of the tides occurs. Why is there a corresponding bulge of water on the other side of the earth?
2007-09-04 03:21:21 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Geography
Tides are caused by the motion of the moon around the earth, not by the rotation of the earth.
2007-09-04 04:05:48 · answer #1 · answered by fangtaiyang 7 · 2⤊ 1⤋
The gravitational attraction of the Moon produces two tidal bulges on opposite sides of the Earth.
Without getting too much into the technical details, there are two bulges because of the differential gravitational forces. The liquid at point A is closer to the Moon and experiences a larger gravitational force than the Earth at point B or the ocean at point C. Because it experiences a larger attraction, it is pulled away from the Earth, toward the Moon, thus producing the bulge on the right side. Loosely, we may think of the bulge on the left side as arising because the Earth is pulled away from the water on that side because the gravitational force exerted by the Moon at point B is larger than that exerted at point C. Then, as our idealized Earth rotates under these bulges, a given point on the surface will experience two high and two low tides for each rotation of the planet.
The realistic situation is considerably more complicated:
See the link.
2007-09-04 04:11:15 · answer #2 · answered by Anonymous · 4⤊ 0⤋
The tide is also affected by the sun's gravity, as well as the rotation of the earth. All three of these factors lead to a complex movement of the seas around the earth. The strongest factor is the moon's gravity, but other factors include the sun's gravity, centripetal forces generated by the earth's rotation, rebounding forces, etc. Check the wikipedia link.
2007-09-04 03:38:18 · answer #3 · answered by dansinger61 6 · 1⤊ 0⤋
they have distinctive origins. The tide raising forces of the moon might purely advance one tide per day, on the component of the Earth dealing with the moon. the 2d tide is raised via the centripetal acceleration of the earth-moon equipment around its centre of gravity - ie the tidal bulge is "throw" outwards via the rotation approximately this component. those 2 outcomes don't have the comparable importance.
2016-10-09 22:31:27 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Simple answer... the moon pulls the water that's on the near side away from the earth, but it pulls the earth away from the water that's on the far side!
2007-09-04 04:06:30 · answer #5 · answered by TurtleFromQuebec 5 · 4⤊ 0⤋
as simply as possible
the water closest to the moon experiences most gravitation and bulges towards the moon.
the water farthest from the moon experiences least gravitation and is left behind and therefore bulges away from the moon
2007-09-05 13:50:51 · answer #6 · answered by B West 1 · 0⤊ 0⤋
the moon pulls the water as it passes earth, hence since water is moving from one side the opposite end must get lower. if there was no low tide on the other side of the earth, that would mean that somehow billions of gallons of water are being created out of nothing.
take a straw and glass of water....suck water in straw right up to your lips and hold, the water level went down. now look in mirror, realize your an idiot....
2007-09-04 07:52:52 · answer #7 · answered by ron197192064 4 · 0⤊ 3⤋
the tides work on 12 hour cycles not 24hr .rotational pull of gravity.
2007-09-08 00:38:14 · answer #8 · answered by country bumpkin [sheep nurse] 7 · 0⤊ 0⤋
Because of the gravitational pull of the moon in the morning and evening - thanks deuces
2007-09-05 11:32:21 · answer #9 · answered by Kalli 3 · 1⤊ 0⤋