10 points to the one who can solve this easy problem?

Question

A pair of scissors cost $8 less than a knife. If 3 pairs of scissors and 2 knives cost $86, find the cost of 1 pair of scissors.

Answer 1

S +8 = K

3S + 2K = 86.


Put top into bottom:

3S + 2S + 16 = 86

5S = 70.

S = $14.

Answer 2

Lets take the price of the scissors to be $x. Since it is $8 less than a knife. A knife cost $(x+8).
3 X $(x) + 2 X $(x+8) = $86
$3x + $2x +$16= $86
$5x = $70
$x = $14
A scissors cost $14

Answer 3

y=cost of a pair of scissors
x= cost of knife
so bye question y=x-8

3*cost of scissors +2*cost of knives=86
3*y+2*x=86
3(x - 8) + 2 x = 86
3x - 24 + 2x = 86
5x = 110
x = 22.
Knives cost x =$22
Therefore Scissors cost y=x - 8= $22 - $8 = $14

Answer 4

let cost of 1 scissor x
let cost of knives be x+8
cost of 3 knives 3x
cost of 2 knives 2(x+8)
total cost = 86$
3x+2(x+8)=86$
3x+2x+16=86$
5x=86-16
x=70/5
x=14$
cost of scissor is 14$

Answer 5

This problem can be solved using simple equation
Sccisors=x
Knife=y
1. the equation is: 3x+2y=86
2. If scissor cost 8 dollars less then knife: x=y-8
so
3. 3*(y-8)+2y=86
4. 3y-24+2y=86
5. 3y+2y=86+24
6. 5y=110
7. y=22
8. x=22-8
x=14.

Solution check:
3*14+2*22=86

Answer 6

x = cost of the scissors
y = cost of the knives

x = y - 8

3x + 2y = 86

Solve equation 1 for y:

y = x + 8

Plug that into equation 2:

3x + 2(x + 8) = 86
3x + 2x + 16 = 86
5x = 70
x = 14

So, the scissors cost $14

Answer 7

k-8=s
3s+2k=86
3s+2s+16 =86 5s= 70 so s = $14 and k= $22

Answer 8

3(x - 8) + 2 x = 86

3x - 24 + 2x = 86

5x = 110

x = 22. (i.e. Knives cost $22)

Therefore Scissors cost $22 - $8 = $14

To check.....

3 x $14 + 2 x $22 = 86

42 + 44 = 86 (Hence Proved)

10 points please my good man......

Answer 9

s = (k - 8)

3s + 2k = 86
3(k - 8) + 2k = 86
3k - 24 + 2k = 86
5k = 110
k = $22

s = 22 - 8
s = $14

A pair of scissors costs $14

Answer 10

14$