can u please solve the following simple mathematical question for me?

Question

1.If the radius of a cone is increased by 100%, its volume will be increased by what %? how?
2. What should be the length of a rope by which a cow must be tethered to graze an area of 2464 m sq.? how?
3. (sq root of 2 minus 1) upon (sq root of 2 + 1)? how?

Answer 1

Question 1
V1 = (1/3) π r ² h
V2 = (1/3) π ( 2 r ) ² h
V2 = (1/3) π (4 r ²) h
V2 = 4 (1/3) π (r ²) h
V2 = 4 V1
Increase = 4 V1 - V1 = 3 V1
% increase = (3V1) / V1 x 100 = 300 %

Question 2
π r ² = 2464
r ² = 2464 / π
r = 28
Length of rope = 28 m

Question 3
( √2 - 1 ) / ( √2 + 1)
( √2 - 1) (√2 - 1 ) / ( √2 + 1) (√2 - 1 )
( 2 - 2√2 + 1 ) / ( 2 - 1 )
( 3 - 2√2 )

Answer 2

1. 50%
2. 1232 m long. Tie it to the stake and the cow can graze in a full circle.
3. .578

Answer 3

1.by 1000 %

2. squareroot of 2064

3. 0.414/2.414

Answer 4

if it is simple do it yourself


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