lim [(√3+x)-(√3)] / x
x => 0
what is the limit?
2007-09-04 02:46:29 · 4 answers · asked by Daniel B 1 in Science & Mathematics ➔ Mathematics
multiply and divide by sqrt(3+x)+sqrt(3)
you get
x/(sqrt(3+x)+sqrt3)*x .Simplify x and you get 1/(2sqrt3)=1/6*sqrt3
2007-09-04 02:57:28 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
multiplying numerator and denominator by sqrt(3+x) +sqrt(3)
(a+b)(a-b)=a^2-b^2
question becomes ( (3+x) -3 )/[ x (sqrt(3+x)+sqrt(3) ) ]
cancelling x and applying the limit x=0,
=1/(2*sqrt(3) )
2007-09-04 02:58:16 · answer #2 · answered by MathStudent 3 · 0⤊ 0⤋
it is: 1
why?
explication:
lim((sqrt(3)+x)-(sqrt(x))/x=
lim(x+sqrt(3)-sqrt(3))/x=
lim(x/x)=lim1=1
2007-09-04 03:10:28 · answer #3 · answered by bar'wita 2 · 0⤊ 0⤋
like they had said
2007-09-07 22:42:11 · answer #4 · answered by jaycellann_20 2 · 0⤊ 0⤋