2(x - 2) - 15 = x + 1
2x - 4 - 15 = x + 1
x = 20
2007-09-07 21:08:14
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answer #1
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answered by Como 7
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a) Multiply both sides of the equation by 10:
10*(x-2)/5 – 10*3/2 = 10*(x+1)/10
b) Simplify:
2*(x-2) – 5*3 = x + 1
c) Do the multiplications:
2*x – 4 – 15 = x + 1
d) Sum:
2*x – 19 = x + 1
e) Subtract x from both sides of the equation:
2*x – x – 19 = x – x + 1 --> x – 19 = 1
f) Add 19 to both sides of the equation:
x – 19 + 19 = 1 + 19 --> x = 20
2007-09-04 09:41:49
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answer #2
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answered by Anthony P - Greece 2
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multiply throughout by 10,
therefore,
2(x - 2) - 5*3 = (x + 1)
2x - 4 - 15 = x + 1
x = 20
~chillax~
2007-09-04 09:30:53
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answer #3
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answered by raja 2
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x=20
2007-09-04 09:37:46
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answer #4
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answered by Sasi Kumar 4
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Multiply both sides by the LCM of denominators to remove the denominators. LCM of 5,2 and 10 is 10
multiplying, you will get
2(x-2) - 15 = x+1
or 2x-4-15 = x+1
or 2x-x = 1+15 + 4=20
or x = 20
2007-09-04 09:37:08
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answer #5
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answered by Indian Primrose 6
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(2x - 4)/10 - 15/10 = (x +`1)/10
2x - 4 - 15 = x +`1
x = 20
2007-09-04 09:32:47
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answer #6
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answered by gebobs 6
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[(2x-4)-15]/10 = (x+1)/10
(30x+60)/10 = (x+1)/10
300x+600 = 10x+10
300x-10x = 10-600
290x = 590
x = 590/290
x=2.04
2007-09-04 10:08:26
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answer #7
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answered by Gatsheni 1
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the answer of your question is 20.if u want the written solution contact meat divyang_gupta2002@yahoo.com
2007-09-04 09:39:17
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answer #8
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answered by dabu 1
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