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Calculate the percentage of nitrogen in 1 mole of the above fertilizers.
[ Relative atomic mass: H, 1; C,12; N,14; O, 16; P, 31; S, 32 ]

Which of the above fertilizer is the most suitable for the growth of plants? Explain your answer.

2007-09-04 01:54:03 · 4 answers · asked by jack_hock2003 1 in Science & Mathematics Chemistry

why urea is most suitable?
can u explain 4 me

2007-09-04 04:03:37 · update #1

4 answers

1.
3NH3 + H3PO4 >> (NH4)3PO4
MM = 149 g/mol
in 1 mole there are 3 N ( 14 x 3 = 42)
% = 42 x 100 / 149 = 28.2 %

2.
HNO3 (aq) + NH3 (g) >> NH4NO3 (aq)
MM = 80 g/mol
% = 28 x 100 / 80 = 35
3.
two reactions take place in the formation of urea from NH3 and CO2
a) 2 NH3 + CO2 >> H2NCOONH4 ( ammonium carbamate )
b) H2NCOONH4 >> (NH2)2CO
MM = 60 g/mol
% = 28 x 100 / 60 = 46.7

Urea is the most suitable

2007-09-04 02:17:05 · answer #1 · answered by Dr.A 7 · 0 0

Chemical Formula For Ammonium Phosphate

2016-12-08 22:46:02 · answer #2 · answered by ? 4 · 0 0

Ammonium Phosphate Chemical Formula

2016-10-03 13:04:36 · answer #3 · answered by Anonymous · 0 0

Well, Calcium = Ca with a charge of +2 Nitrate = NO3 with a charge of -1 Sodium = Na with a charge of +1 Phosphate = PO4 with a charge of -3 When putting them together, you have to balance the charges. Then, to find the product, know that it is a double replacement reaction. Final Equation: 3Ca(NO3)2 + 2Na3(PO4) ----> Ca3(PO4)2 + 6Na(NO3)

2016-03-18 01:40:02 · answer #4 · answered by Anonymous · 0 0

3 NH4OH + H3PO4 -> (NH4)3PO4 + 3 H2O

NH4OH + HNO3 -> NH4NO3 + H2O

NH4CNO -> NH2CONH2

Most suitable (long term) is urea.

2007-09-04 02:17:43 · answer #5 · answered by ag_iitkgp 7 · 0 0

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