2007-09-03 20:41:58 · 17 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
can you explain it to me please
2007-09-03 20:50:26 · update #1
(x y ) (x + y) / (x + y) = x y
2007-09-07 19:55:20 · answer #1 · answered by Como 7 · 4⤊ 0⤋
If you mean
(x^2 y + x y^2) / x+y
= (x y ) (x + y) / x + y = y (x+y) +y = xy + y^2 + y
Whereas if you mean
(x^2 y + x y^2) / (x+y)
= (x y ) (x + y) / (x + y) = x y
2007-09-11 17:39:25 · answer #2 · answered by Siddhartha Basu 4 · 0⤊ 0⤋
numerator=(x^2 y + x y^2)
=take xy as common from it
=xy(x+y)
denominator=(x+y)
so nr/dr=xy(x+y)/(x+y)
=xy
now how did we come to know that we should take xy as common
since the denominator is (x+y) ....we must generate (x+y) in Nr
so try thinking on this line
2007-09-11 20:07:47 · answer #3 · answered by mail.mayur 1 · 0⤊ 0⤋
= (x^2 y + x y^2) / x+y
= xy
Answer: xy
2007-09-09 22:04:24 · answer #4 · answered by Jun Agruda 7 · 4⤊ 0⤋
factor our an x y from the numerator
(x y * ( x + y) ) / (x + y)
there is an x+y in both the numerator and the denominator so this cancels out and you are left with ( x * y ) as the simplified solution.
2007-09-10 19:31:25 · answer #5 · answered by Merlyn 7 · 1⤊ 0⤋
Look at the top set of varibles if we can factor out (x+Y) we can cancel these out as the bottom is (x+y)
Factor out xy
xy(x+y)/(x+y)
We now can divide with(x+y)
we end up with xy
2007-09-08 11:11:53 · answer #6 · answered by scide i 2 · 1⤊ 1⤋
(x^2 y + x y^2) / x+y
= xy(x+y)/(x+y)
=xy
(Answer)
2007-09-09 17:07:42 · answer #7 · answered by defeNder 3 · 1⤊ 0⤋
(x^2y+xy^2) / x+y
is the same as
xy( x +y) / x+y = xy
the (x+y) cancel each other out
2007-09-11 06:46:37 · answer #8 · answered by Will 4 · 0⤊ 0⤋
xy
2007-09-11 14:28:40 · answer #9 · answered by luv2skater 3 · 0⤊ 0⤋
xy
2007-09-09 01:15:54 · answer #10 · answered by bansal 4 · 1⤊ 0⤋
answer is xy
2007-09-10 18:27:18 · answer #11 · answered by Anonymous · 1⤊ 0⤋