how do you find the standard form of the equation of the line with slope 2 passing through the point (2,3)?

Question

answer: 2x-y=1

Answer 1

this is formula
y - y1 = m(x - x1)
m= is the slope
x = 2
y = 3

so

y - 3 = 2(x - 2)
y - 3 = 2x - 4
y = 2x -4 + 3

answer is

y = 2x - 1 or 2x -y = 1

Answer 2

In standard form, the equation is y = mx + c, where m is the gradient, and c the intercept on the y-axis. You are given that m = 2, so

y = 2x + c

You are also given that when x = 2, y = 3, so

3 = 2x2 + c, so

3 = 4 + c, so

-1 = c, and

y = 2x - 1. Hope this helps, Twiggy.

Answer 3

hi,
the solution for ur problem starts with the std form of equation of a line passing thru (x1,y1) i.e.

y - y1 = m (x - x1)
where
m is the slope of the line

acc to ur problem the line passes thru (2,3)

so we can write the equation as,

y - 3 = 2 * ( x - 2 )

i.e. y - 3 = 2x - 4
shifting terms we get,

2x - y = 1
hope it helps u in understanding the equation.

Answer 4

first of all, you need to find it in slope-intercept form, which is y=mx+b. to do that, you plug the point in with the slope as so: 3=2(2)+b and you get "b" to be -1. that means that y=2x-1. from there, standard form is ax+by=c. you can subtract the y and add the 1, or subtract the 2x, but i suggest keeping your x positive. so you would wind up with 2x-y=1. that is standard form. hope i helped. if i am wrong, someone correct me.

Answer 5

purely take the equation y=mx+b and replace interior the x and y values of the element(-7,-2) and m for the slope. resolve for the variable b. the familiar equation ought to look like y=mx+b with the m and b substituted for their easily values.

Answer 6

y - 3 = 2(x - 2)
y - 3 = 2x - 4
y = 2x - 1
2x - y = 1