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5w to the 5th power x to the 5th power multiplied by 6w to the 5th power x to the 5th power
______________________Divided by
2w to the 5th power x to the 5th power

2007-09-03 20:17:39 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Hi,

It took a little while to figure out what you were saying up above, but I think I got it.

Let

A = 5·x^5

Then, your equation (if I understand it correctly) looks like

(5·wᴬ · 6·wᴬ) / 2·wᴬ

= 30·w²ᴬ / 2·wᴬ

= 15 wᴬ

= 15·w^(5·x^5)

James

2007-09-03 20:33:00 · answer #1 · answered by ? 3 · 1 0

if you mean this:

......(5w⁵x⁵)( 6w⁵x⁵)
--------------------------------
........2 w⁵x⁵

then one set of w⁵x⁵from the top and the bottom cancel leaving the second w⁵x⁵ and the 6 and 2 reduce to a single 3 in the numerator to get:

......15w⁵x⁵

2007-09-04 03:36:41 · answer #2 · answered by 037 G 6 · 1 0

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