write 4th degree poly with specific x-intercepts.?

Question

x=-2,2,5

Thanks both of the first two.
Gonna give to first response.

Answer 1

To get a polynomial with specific zero's (x intercepts) at x values of x1, x2...... xn, just form (x-x1)*(x-x2).........(x-xn). In your case
P(x) = (x+2)*(x-2)*(x-5)*(x-whatever you want)
Multiply it out and you're done.

HTH

Doug

Answer 2

You need to multiply by a, the first coefficient

And there are only 3 roots, there should be a fourth one

P(x) = a (x-2)^2 (x-5) (x- ?). Plug here the fourth root

Ilusion

Answer 3

y = (x+2)(x-2)(x-5)(x-z), where z is arbitrary. You can do the indicated mulitplication.