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8 answers

1100=20x+50(37-x)
1100=20x+1850-50x
1100=-30x+1850
1100-1850=-30x+1850-1850
-750=-30x
-750/-30=-30x/-30
25=x
25 $20s and 12 $50s

2007-09-03 18:55:22 · answer #1 · answered by Katie B 3 · 2 0

12 --50s... and 25--20s.

the way i figured it out was to start out with all 20s. This amout is 37 x 20 =740.

the difference between 1100-740=360.
the difference between 50 and 20 is 30.
if you take the 360 you still need to get and divide by 30 (50-20)=12.
That means you need to make 12 of the bills 50s, and that leaves 25 bills that are 20s
12 x 50=600
25 x 20=500
600+500=1100

2007-09-03 18:51:09 · answer #2 · answered by Anonymous · 1 1

let f be the number of fifty dollar bills and t be the number of 20 dollar bills.

Then:

f+t =37 this is the equation for the total number of bills

50f + 20t = 1100 this is the equation for the money

solve by substitution:

t = 37 -f

50f + 20(37-f) = 1100
50f +740 -20f = 1100

30f = 360
f =12

t = 37-12=25

2007-09-03 18:56:10 · answer #3 · answered by VampireDog 6 · 1 0

Let x= number of 20s

x(20)+(37-x)50=1100
20x+1850-50x=1100
-30x=-750
x=25
25 twenties and 12 50s.

2007-09-03 18:54:07 · answer #4 · answered by Nelson_DeVon 7 · 1 0

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2016-10-17 21:34:35 · answer #5 · answered by ? 4 · 0 0

no. of 50s = x
no. of 20s = y

eqn I : x+y = 37
eqn II: 50x + 20y= 1100

therefore x= 12 i think......solve the equations and check.

2007-09-03 18:52:10 · answer #6 · answered by Anonymous · 1 0

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2007-09-03 18:49:51 · answer #8 · answered by AerosX 2 · 1 2

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