Hollie
Torie
Jeanie
Zoey
Mali {Mar-li}
Carlie
Kali {Kal-i}
Amelie
Abbie
Bonnie
Darcie/Darcy
Kacie
Lanie
Libbie/Libby
Lacie/Lacy
Stacie
Ashley
Hadlie
Hailie
Gabie
Maddie
Annie
Baylie
2007-09-03 17:26:46
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answer #1
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answered by Anonymous
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0⤊
0⤋
Ashley Britney Courtney Daphne Emily Felicity Gabbey Hailey Ivory Jessie Kasey Lillie Mary Natalie Penelope Rosalie Stephenie Tiffany Valerie Wendy
2007-09-03 17:21:16
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answer #2
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answered by missy 3
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1⤋
Stacy, Becky, Lily, Evie, Ashley, Aubrey, Bailey, Bethany, Brittney, Courtney, Delaney, Emily, Felicity, Kelsey, Kenley, Heidi, Kalani, Katie, Leslie, Lucy, Mackenzie, Natalie, Stefanie,
2007-09-04 04:43:12
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answer #3
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answered by Holly C 3
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1⤋
Vicky, Terry, Sandy, Julie, Jamie, Linnie, Amy, Elly, Emily, Kerry, Cassie, Lindsay, Romy, Nancy, Tansy, Rosie, Gracie, Nelly, Chloe, Zoe, Molly, Polly, Sally, Mary, Tracy, Stacey, Casey, Chelsea, Macy, Maisie, Daisy, Poppy, Penny, Emmy, Jennie, Josie, Judy, Kelly, Kelsey, Carly, Lindy, Debby, Jessie.......
2007-09-03 17:16:34
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answer #4
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answered by adoptive mom 4
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1⤋
Marnie, Penny, Jodi, Natalie, Bethany, Libby, Jamie, Stephanie, Amy, Angie, Cathy, Sally, Stacey, Nikki, Penelope, Sophie, Lottie, Joanie, Katie, Franny, Betty, Kylie, Kellie, Nellie, Lanie, Christie, Bobbi, Becky, Lexi, Gypsi, Urlie, Hettie, Gracey, Danni, Toni, Bonny, Connie, Lucy.
Just to name a few!
2007-09-03 16:52:03
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answer #5
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answered by Anonymous
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1⤊
1⤋
Leilani, Bethany, Brittany, Tori, Sallie, Remy
2007-09-03 16:46:20
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answer #6
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answered by Anonymous
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0⤋
Maggie
Kari
Ashlie
Aimee/Amie
Brittanie
Tiffany
Lindsay
Hallie
Lani
Bethany/ie
Stephanie
Kylie
Kaley
Molly
Bailie
Emily
Gracie
Natalie
Katie
2007-09-04 06:20:57
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answer #7
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answered by Anonymous
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0⤋
Lori, Merilee, Kerry, Kelsey
2007-09-03 16:45:42
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answer #8
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answered by dr_usual 3
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1⤋
Mackenzie
2007-09-03 17:01:23
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answer #9
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answered by colorfulswanson 2
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0⤋
Brittany, Haley, Kiley, Mandi, Lilly, Terri, Sophie.
2007-09-03 16:50:37
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answer #10
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answered by TJTB 7
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0⤊
1⤋
Kimberly, Terry, Shelly, Kari, Kelsey, Stacy
2007-09-03 16:47:46
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answer #11
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answered by Anonymous
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0⤊
1⤋