its an easy question i know, but i dont get it
"the perimeter of a rectangle is is 50 ft. express its area 'A' as a function of length 'L' of a side"
2007-09-03 16:30:57 · 3 answers · asked by nasgmx,zncv xc 2 in Science & Mathematics ➔ Mathematics
Let
P = perimeter rectangle
L = length rectangle
W = width rectangle
A = area rectangle
P = 50 ft.
P = 2L + 2W
50 = 2L + 2W
25 = L + W
W = (25 - L)
A = LW = L(25 - L) sq. ft.
2007-09-03 16:42:00 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
If L is the length and B is the breadth
perimeter = 2(L+B)
50 = 2(L+B)
L+B = 25
B = 25 -L
Area = L*B = L(25 - L)
2007-09-03 23:44:46 · answer #2 · answered by qwert 5 · 0⤊ 0⤋
The lenth of one side can RANGE from 0 to 1/2 the perimeter.
Find LIMITS of area! Then Function!
2007-09-03 23:43:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋