2007-09-03 14:05:59 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x=t+1, so t=x-1
Substitute x-1 wherever you see t
y=(x-1)^2+(x-1)
y=x^2-2x+1+x-1
y=x^2-x
y=x(x-1)
2007-09-03 14:13:04 · answer #1 · answered by Grampedo 7 · 0⤊ 0⤋
There are two equations involved here. Substitute value of t from 1st equation after rearranging (t=x-1) to 2nd equation (y=x-1)^2+(x-1); simplifying you have y=x^2-x
2007-09-03 21:22:40 · answer #2 · answered by jonalis 1 · 0⤊ 0⤋
Since x = t + 1, t = x - 1. Then y = (x-1)^2 + (x-1)
(x-1)^2 = (x-1)(x-1) = x^2 - 2x + 1
So y = x^2 - 2x + 1 + x - 1
This simplifies to y = x^2 - x
2007-09-03 21:13:31 · answer #3 · answered by hayharbr 7 · 0⤊ 0⤋
x = t + 1
t = x-1
y = t^2 + t = (x-1)^2 + (x-1)
= x^2 -2x + 1 + x - 1
= x^2 - x
2007-09-03 21:14:52 · answer #4 · answered by norman 7 · 0⤊ 0⤋
y = x (x-1) = x^2 - x
= (t^2 +2t +1) - (t + 1)
= t^2 + t
2007-09-03 21:19:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x= t+1 ( that means, t= x-1)
replace every " t" by "x-1" in 2nd equation.
y= (x-1)^2 + (x-1)
y= ( x2 -2x+1 +x- 1)
y = x2-x
2007-09-03 21:16:07 · answer #6 · answered by Anonymous · 0⤊ 0⤋