how would you graph 4x+3y=0?

Question

u can just show me the method

Answer 1

this is a linear equation

the standard form is y=mx+b m=slope and b is the y intercept

4x + 3y = 0 equals 3y = -4x equals y = -4/3 x

when x = 0 than y = 0 when x = -3/4 than y =1

Answer 2

4x + 3y = 0

One way to easily graph this line is to change this into slope-intercept form, y = mx + b. Algebraically we can achieve this.

3y = -4x

Multiply both sides by 1/3,

y = (-4/3)x

Which is the same as

y (-4/3)x + 0

This tells us that the slope is m = -4/3 and the y-intercept is 0.

slope = rise over run = rise/run

Since the y-intercept is 0, the line will go through the point (0,0), so graph a dot at (0,0).

The "run" is 3, and the "rise" is 4. The fact that the slope is negative means the line will be sliding downward (similar to the "\" symbol).

From the point (0, 0), move 3 units to the *left* and 4 units up. Draw a dot, and connect the two existing dots. That's your line.

Answer 3

4x 3y 0

Answer 4

First you would move 3y to the other side of the equation. It would look like
4x= -3y

then, divide both sides by -3.
y= -4/3x

Now, it's in y=mx+b format. the m= the slope of the graph, and the b would equal the y-intercept, but in this case it would be 0.

Answer 5

rearrange the equation y = -4/3x
find 2 point...when y = 1 x = -3/4
when x = 1 y = -4/3

Answer 6

3y= -4x
y=-4/3x