-1............x-4
___ = _____
x-3........x^2-27
Ignore the periods.
2007-09-03 11:09:11 · 5 answers · asked by PumaPepper 2 in Science & Mathematics ➔ Mathematics
cross multiply
so
-x^2 + 27 = x^2 - 7x +12
2x^2 -7x - 15=0
(2x+3)(x-5)=0
x=(-3/2) and x=5
2007-09-03 11:17:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Cross multiply getting:
-1(x^2-27) = (x-3)(x-4)
-x^2+27 = x^2 -7x+12
2x^2-7x -15 = 0
(2x+3)(x-5)=0
x= -3/2 and x - 5
2007-09-03 18:18:48 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
Multiply by (x - 3)(x^2 - 27):
- x^2 + 27 = (x - 4)(x - 3)
= x^2 - 7x + 12
2x^2 - 7x - 15 = 0
(2x + 3)(x - 5) = 0
x = - 3/2 or x = 5.
2007-09-03 18:19:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋
-1/(x - 3) = (x - 4)/(x^2 - 27)
Multiply both sides by the LCD (x - 3)(x^2 - 27)
-1(x^2 - 27) = (x - 4)(x - 3)
-x^2 + 27 = x^2 - 7x + 12
-2x^2 + 7x + 15 = 0
2x^2 - 7x - 15 = 0
(x - 5)(2x + 3) = 0
x = 5, x = -3/2
Both answers check in the original equation
2007-09-03 18:25:06 · answer #4 · answered by kindricko 7 · 0⤊ 0⤋
cross multiply
2007-09-03 18:23:36 · answer #5 · answered by rudy 2 · 0⤊ 0⤋