What is the equation of the line that passes through (0, -3) (4, 0)?

Answer 1

Hi,

y = 3/4x - 3

To find the slope, do (y2 - y1)/(x2 - x1) = m. This is:
(0 - (-3))/(4 - 0) = 3/4 for the slope of the line.

If you take the formula y = mx + b and substitute a point for (x1,y1) and the slope for m, you can get the following equation to solve for "b":

y = mx + b
0 = 3/4(4) + b
0 = 3 + b
-3 = b

So the equation in slope-intercept form is y = 3/4x - 3.

I hope that helps!! :-)

Answer 2

Hello

First step is to find the slope: (y2-y1) / (x2-x1) = (0-(-3)) / (4-0) = 3/4 = slope = m

So lets us the slope-intercept form: y = mx+b

Plug in one of the points from above: 0 = (3/4) 4 + b. Thus we know b = -3.

So our equation is y = (-3/4)x - 3.

Hope this helps

Answer 3

first find the slope m = ( -3 - 0 ) / ( 0 - 4) = -3/-4 = 3/4

use point slope form of the line to get the equation

y - y1 = m * (x - x1)
y - -3 = m * (x - 0)
y + 3 = 3/4 * x
y = 3x/4 - 3

Answer 4

F(x)=ax+b

-3=0+b
b=-3
also,
0=a4+b
4a=-b
a=3/4

so we have F(x)=3/4x-3

Answer 5

m = (0 + 3) / (4 - 0)
m = 3 / 4
y - 0 = (3/4) (x - 4)
y = (3/4) x - 3

Answer 6

y= 0.75x - 3