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A hot dog bun (volume 240 cm3) with a density of 0.15 g/cm3 is crushed in a picnic cooler into a volume of 195 cm3.what is the new density of the bun?

2007-09-03 10:30:24 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

weight of hot dog bun = 240 cm^3 x 0.15 g/cm^3 = 36 gram
36 gm / 195 cm^3 = 0.185 g/cm^3

2007-09-03 10:39:28 · answer #1 · answered by skipper 7 · 0 0

The mass of the bun is .15g/cm3 multiplied by 240 cm3 = 36gm

The new density is 36 gm/195cm3 = .184 g/cm3

2007-09-03 10:39:40 · answer #2 · answered by Rich Z 7 · 0 0

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