How do you solve this problem?

Question

___V___ - _8_
(v^2-2v-3) (v+1)

Answer 1

There is nothing to solve. This can be simplified as follows:

v/(v^2 - 2v - 3) - 8/(v + 1) =
v/((v - 3)*(v + 1)) - 8*(v - 3)/((v - 3)*(v + 1)) =
(v -8v + 24)/(v^2 - 2v -3) = (-7v + 24)/(v^2 - 2v -3) .

Answer 2

In what way solve, there's no equals sign

but we can manipulate it a little

assuming I've read the line correctly

v^2-2v-3 factorizes into (v+1)(v-3)

using that as the common denominator
we get

(v-8(v-3))/(v+1)/(v-3)

or

(-7v+24)/((v+1)(v-3))

or (24-7v)/(v^2-2v-3)

which is a little nicer / tidier than the original

but I still say you cannot solve it for numerical values of v
without an equals sign, so there's nothing to solve