Factor Completely: am+2m+an+2n?

Question

Okay, so the variables totally threw me off, can someone guide me through this step by step?

Answer 1

m (a + 2) + n (a + 2)
(a + 2) (m + n)

Answer 2

start up by putting off a factor of two. The expression will become: 2(n^2 - m^2 + 20m - one hundred) think of of the contents of the parentheses this way: n^2 - (m^2 - 20m + one hundred) This bit … m^2 - 20m + one hundred … is a pleasing sq.. that's written as (m - 10)^2 So n^2 - (m^2 - 20m + one hundred) = n^2 - (m - 10)^2 Bingo! the version between 2 squares. n^2 - (m - 10)^2 = (n + (m - 10))(n - (m - 10)) = (n + m - 10)(n - m + 10) placed all of this at the same time, remembering the preliminary factor of two … answer: 2n^2 - 2m^2 + 40m - 200 = 2(n + m - 10)(n - m + 10) ––––––––––––––––––––––––––––––

Answer 3

step 1) look for specific numbers in the terms which contain the variables you wish to factor out, in this case both 'n' and 'm' have an 'a' and a '2' in common

(a)m + (2)m + (a)n + (2)n

step 2) split up the variable and the coefficient (if there is one)

(a)(m) + (2)(m) + (a)(n) + (2)(n)

step 3) simplify like variables, in this case the m's and n's

(a+2)m + (a+2)n

step 4) in this case, you'll need to do it again with (a+2) a single term

(a+2)(m+n)

Answer 4

am + 2m + an + 2n = a (m + n) + 2 (m + n) = (a + 2) (m + n)

Answer 5

am+2m+an+2n
=m(a+2) +n(a+2)
=(m+n)(a+2)

Answer 6

I think the answer to your problem is the following:

(m+n)(a+2)

if you multiply them out you will get your original problem. That is a way of checking your answer. Hope it helps!

Answer 7

am+2m+an+2n
m(a+2)+n(a+2)
The common factor is now (a+2)
(a+2)(m+n)

Answer 8

m(a+2) + n(a+2)

(a+2)(m+n)

I think that is correct. Good Luck!