Laplace Transform?

Question

What is the laplace transform of cos(2t-(pi/6))

I tried it, and got
[s/((s^2)+4)] e^(-s(pi/12))

does that look about right?
For the record, I used the time shifting property.

Answer 1

Without doing the integration, the easiest way seems to be to use trig formulae and standard results

cos(2t - π/6) = cos2t cos π/6 + sin2t sinπ/6

...................... = ½√3 cos2t + ½sin2t

L[cos(2t - π/6)] = ½√3 L[cos2t] + ½L[sin2t]

.......................... = ½√3 (s/(s² + 4)) + ½ ( 2 /(s² + 4))

.......................... = ½(s√3 + 2)/(s² + 4)

Answer 2

above answer looks good