In order to qualify for a racing competition the a racing car must achieve minimum speeds 250km/h on a 1600 m long track. The car travels at 230km/h for the first half of the track, what must be the minimum avg speed of the car during the second half in order to qualify.
Anything will work such as which formula to use and etc.
2007-09-03 07:51:31 · 4 answers · asked by RickySingh2006 2 in Science & Mathematics ➔ Physics
0.8 = 230* t1 ( t1 in hours)
0.8 = x*t2
1.6 = 250(t1+t2)
t1= 0.8/230 and t2= 1.6/250-0.8/230 = 0.0029 h
so x= 273.81 km/h
2007-09-03 08:07:40 · answer #1 · answered by santmann2002 7 · 1⤊ 1⤋
If the car travels at a speed of 230 km/h half the distance and x km/h the other half and the minium average is 250km/h, then (230 + x ) / 2 = 250 >>> 230 + x = 500>>> x = 500-230 >>> x=270 km/h
Test (230+270) /2 = 250km/h average speed
the second half he traveled at 270 km/h
2007-09-03 15:06:03 · answer #2 · answered by ? 3 · 0⤊ 0⤋
If the car travels at 230 km/h for the first 800 m, then it must travel 270 km/h for the second 800 m in order for the average for the entire 1600 m to be 250 km/m.
(230 + x)/2 = 250
2007-09-03 14:58:44 · answer #3 · answered by JM 4 · 0⤊ 0⤋
i think i cn do this if i try real hard :S bt y dnt u try urself...then come back and ask for help if u cnt do t :0 best of luck :)
2007-09-03 15:03:35 · answer #4 · answered by spotty 3 · 0⤊ 1⤋