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state the domain of f(g(x)) if f(X) = squareroot x+2 and g(x) =3/x

2007-09-03 07:21:06 · 3 answers · asked by Ballerina 5 in Science & Mathematics Mathematics

3 answers

it has to be x don't equal 0
x>=-2
so
the domain is x>-2 -{0}

2007-09-03 07:31:13 · answer #1 · answered by modalmasri 2 · 0 0

If f(x) is the square root of (x+2) (i.e. f(14)=4), then x can be all real numbers except 0 and cannot be less than -6. If f(x) is the square root of x and then adding two (i.e. f(16)=6), then the domain is x has to be greater than 0.

To solve these problems just put g(x) everywhere you see an x in the equation f(x). Then substitute 3/x for every g(x) you see in the f(x) equation. So the equation you lined out would look like
square root (3/x)+2

2007-09-03 14:34:56 · answer #2 · answered by Thomas Rissky 1 · 0 0

domain of f(x) is x>=-2
domain of g(x) is all x not =0
f(g(x)) 3/x>=-2 so 3/x+2>=0 and (3+2x)/x>=0
x<=-3/2 and x >0

2007-09-03 14:32:46 · answer #3 · answered by santmann2002 7 · 0 0

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