Find another vector with the same direction as <-2,4,2> but with lengh 6.?

Question

I should know this but I totally forgot how to do it.
Thank you for the help.

Answer 1

{- 1 2 1} is required vector.

Answer 2

i assume you recognize that given 2 vectors A and B , A dot B = IAI IBI cos T the place T is the perspective between the two .- If A=B , T=0º , cos 0=a million and A dot A = IAI IAI , ie IAI^2 = A dot A If A= (a,b,c,d..n , z) , A dot A = a^2+b^2+ ..... z^2 on your case IAI ^2 = a million^2+2^2+5^2 = a million+4+25 =30 IAI =sqrt 30 The unit vector interior a similar path , is A= IAI , unit vector , so = A/ IAI = (a million/sqrt30) ( a million,2,5)

Answer 3

Unit vector in the given direction is1/sqrt(24)(-2,4,2)
so the vector with length 6 is
6/sqrt24 *(-2,4,2)

Answer 4

the dr's of the vector is -2/rt(24), 4/rt(24) , 2/rt(24)
multiply them with 6 and get ur ans......