3x / 2 + 1/4 ( x-2 ) = 10
3x/2 + 1/4 x - 1/2 = 10 [ i multiplied (x-2) by 1/4]
3x/2 + 1/4x = 10 1/2 [ added 1/2 to both sides of the = sign]
12x/2 + x = 42 [multiplied both sides of equation by 4]
14x / 2 = 42 [ multiplied x by 2/2 and added to 12x/2]
14x = 84 [multiplied both sides by 2]
x = 6 [ divided both sides by 14 ]
2007-09-03 05:32:43
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answer #1
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answered by Will 4
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3x/2 + 1/4(x-2)=10
(3/2)x + (1/4)x - (1/4)2 = 0
(6/4 + 1/4) x - 1/2 = 0
(7/4)x = 1/2
x = (1/2)(4/7) = 2/7
lol im only in 6th grade and i was able to o this lol no offence to u though. Iguess you just have trouble but considering me being only 11 it's pretty surprising.
Well i gave you your work so can you vote me as best answer?
2007-09-03 12:22:14
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answer #2
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answered by Anonymous
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3x/2 + 1/4(x-2)=10
(3/2)x + (1/4)x - (1/4)2 = 0
(6/4 + 1/4) x - 1/2 = 0
(7/4)x = 1/2
x = (1/2)(4/7) = 2/7
2007-09-03 12:19:03
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answer #3
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answered by vlee1225 6
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3x/2 + 1/4(x-2) = 10
3x/2 + 1/4x - 1/2 = 10
2 (3x/2) + 1/4x - 1/2 = (10)2
5x + 1/4x - 1/2 = 20
5 1/4x - 1/2 = 20
+1/2 +1/2
5 1/4x = 20 1/2
____________ divide both sides by 5 and 1/4
5 1/4 5 1/4
x = 4 1/4
2007-09-03 12:28:34
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answer #4
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answered by [[Elle♥Kay]]™ 2
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this translates to:
3X/2 + (X-2)/4 = 10
Multiply the first part X 2 to get a common denominator
6X/4 + (X-2)/4 = 10
Or:
(7X-2)/4 = 10
Multiply both sides by 4
7x-2 = 40
Add 2 to both sides
7X = 42
Divide by 7:
X = 6
2007-09-03 12:23:35
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answer #5
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answered by shektbg 2
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1. 3x/2 +.25x -.5= 10
2. Multiply by 2: 3x+.5x-1=20
3. combine like terms 3.5x= 21
4. Divide x= 6
2007-09-03 12:22:16
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answer #6
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answered by jehu22293 2
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3x/2 + 1x/4 - 1/2 =10
(6x+x)/4=21/2
7x=42
x=6
2007-09-03 12:20:50
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answer #7
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answered by Anonymous
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multiply both sides by 8 to get rid of the fractions: 12x+2(x-2)=80
distribute:12x+2x-4=80
add the Xs: 14x-4=80
add -4 to 80: 14x=84
X=6
2007-09-03 12:20:58
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answer #8
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answered by soso123845 2
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6x/4 +(x-2)/4 = 10
6x +(x-2) = 40
7x -2 = 40
7x = 42
x = 42/7
x = 6
2007-09-03 12:26:29
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answer #9
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answered by Bud M 1
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e=mc2
2007-09-03 12:19:30
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answer #10
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answered by Anonymous
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