iv been getting alot of help for this problem but i cant get the answer for this question.
question:
the 7th graders sold tickets to their play. the tickets cost $3 for students and $6 for adults. one day they sold 79 tickets and collected $375. how many student tickets and how many adult tickets were sold???
2007-09-03 04:50:11 · 8 answers · asked by Nikki 2 in Science & Mathematics ➔ Mathematics
If a are the number of tickets sold for students and b the number sold to parents, we can write 3a + 6b = 375 and a + b = 79
3a + 6b = 375
3a + 3b = 237 ( 79 multiplied by 3)
Subtracting the second equation from the first,
3b = 138
b = 138 / 3 = 46
So, a = 79 - 46 = 33
So, 33 tickets were sold to students and 46 tickets were sold to parents.
2007-09-03 05:01:07 · answer #1 · answered by Swamy 7 · 1⤊ 0⤋
33 student tickets were sold and 46 adult tickets were sold.
You can find this answer by doing the following:
First, you need to set up 2 equations, the first being 3x+6y=375, the second being x+y=79. X will represent the student tickets sold and y will represent the adult tickets sold.
From there, solve the second equation for y: y=79-x
Then plug in that equation into the first equation: 3x+6(79-x)=375
from there, use simple algebra to solve for x, then once you have found x, just put the number you got into the second equation: x+y=79.
2007-09-03 12:10:01 · answer #2 · answered by Love Zelda0 2 · 0⤊ 0⤋
equation:
3s+6a=375
s+a=79
a stands for adult tickets
s for student tickets
at first i tried half and half
40 6 dollar tickets and 39 3 dollar tickets and i got 357 dollar total. each adult ticket more than student ticket i sell gets a 3 dollar increase. so 375-357 equals 18 divided by 3 =6
so i did 46 6 dollar tickets and 33 3 dollar tickets
the result is 375 dollars
and 79 tickets sold
2007-09-03 12:00:12 · answer #3 · answered by hoffster12 4 · 1⤊ 0⤋
here's a hint...
x = # student tickets, y = # adult tickets
total tickets sold was 79, so
x + y = 79
also 3x = amount of $$$ made from student tickets, 6y = $$$ from all of the adult tickets
so $ from students tickets + $ from adult tickets = total $ made
3x + 6y = 375
use the first equation above to eliminate the y value in the second equation, and you will be able to solve for x, and then y........
hope this helps......
2007-09-03 11:57:53 · answer #4 · answered by Mathguy 5 · 0⤊ 0⤋
Let's just say 's' stands for students and 'a' stands for adults.
s + a = 79
3s + 6a = 375
3( 79 - a) + 6a = 375
237 - 3a + 6a = 375
237+ 3a = 375
3a = 138
a = 46
46 + s = 79
s = 33
Check:
46(6) + 33(3) = 375
Hope this helps!!!
2007-09-03 12:08:07 · answer #5 · answered by JakeS 2 · 0⤊ 0⤋
a+b=79
3a+6b=375
a=79-b
3a=237-3b
237-3b+6b=375
237+3b=375
3b=138
b=46
a+46=79
a=33
33 student, 46 adult
to check:
33X3+46X6=375
2007-09-03 12:03:15 · answer #6 · answered by Anonymous · 0⤊ 0⤋
a= number of student tickets
b= number of teacher tickets
a+b= 79
3a+6b = 375
That's all I'll say, you can do the rest.
2007-09-03 12:00:39 · answer #7 · answered by DeltaKilo3 4 · 0⤊ 0⤋
y don't u try to solve it ur self
try going to some math websie look it up on google
2007-09-03 11:59:13 · answer #8 · answered by Anonymous · 0⤊ 1⤋