If we know the solution,it is very easy to form the quadratic equation
Let an quadtratic equation has two solutions 'p' and"q'
then the quadratic equation would be
x^2-(p+q)x+pq =0
Let us take another example
Let the value of x be 5 and -3
Sum of the roots= 5-3=2
Product of the roots=5*-3= -15
therefore the equation would be
x^2-(sum of the roots)x+product of the roots
=>x^2-2x-15=0
Hope it helps you
2007-09-03 04:02:50
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answer #1
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answered by Anonymous
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you cannot find the EXACT equation if you are only given the solution. However you can get a general form. If you have x=2 and x=1, it means that the equation touches the x-axis at 2 and 1.
Therefore, your equation is y=a(x-1)(x-2)
where a is a constant. a cannot be determined useless you are given further information
2007-09-03 11:07:13
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answer #2
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answered by polarbear 1
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Multiply. If you are told "x = 3, x = 2", then multiply (x - 3)(x -2) and set the product equal to 0.
2007-09-03 11:01:39
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answer #3
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answered by Edgar Greenberg 5
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If your solution is the two roots a,b
then (x-a)(x-b)=0
or x²-ax-bx + ab = 0
2007-09-03 11:01:56
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answer #4
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answered by chasrmck 6
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if a and b are the solutions of the quad eq
then the eq is (x-a)(x-b) = x^2 - (a+b)x + ab
2007-09-03 11:02:02
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answer #5
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answered by norman 7
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(x + a) (x + b) = 0
given A and B are solutions
2007-09-03 11:02:09
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answer #6
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answered by Justin Lin 2
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FOIL method
2007-09-03 11:01:49
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answer #7
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answered by reynwater 7
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