A plane flies a distance 180km at an angle 68.0 east of north then flies 240km at an angle 48.0 south of east-

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A plane flies a distance 180km at an angle 68.0 east of north then flies 240km at an angle 48.0 south of east-

When the airport sends out a rescue crew, how far should this crew fly to go directly to this plane?

2007-09-03 02:45:06 · 2 answers · asked by J 1 in Science & Mathematics ➔ Physics

2 answers

Displacement D= sqrt(Dx^2+Dy^2)
Angle= arcTan(Dy/Dx)

x1=180cos(90-68.0) (if I properly understood your "68.0 east of north")'
y1=180sin(90-68.0)
similarly
x2= 240 cos(48.0)
y2= 240 sin(48.0)

Dx=x1+x2
Dy=y1-y2

2007-09-03 03:00:36 · answer #1 · answered by Edward 7 · 0⤊ 0⤋

a simple triangle
one leg at 68 degrees for 180km
one leg at 138 degrees for 240km
complete the rectangle and solve for the unknown side

2007-09-03 03:02:02 · answer #2 · answered by Mike M 4 · 0⤊ 0⤋