Lim x→∞ e^(sinx)?

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Lim x→∞ e^(sinx)?

calculate the limit

2007-09-03 01:51:44 · 2 answers · asked by Deutschjoe 3 in Science & Mathematics ➔ Mathematics

2 answers

this limit does not exist as sin x oscilates between -1 and 1 as x ==> infinity
Take x= 2npi with n==> infinity sin 2npi = 0 and e^0 =1 constant
take x = pi/2+2npi and sin x= 1 and e^1=e.

2007-09-03 02:04:04 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

1/e .. e

2007-09-03 02:06:11 · answer #2 · answered by ? 5 · 0⤊ 0⤋