Given the fact that the number of turns and the current in the solenoid affects the strength of the electromagnet, how does the above two factors exactly influence its strength? Can someone give me an answer in terms of electrons?
2007-09-03 01:14:27 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The Motion of electrons in one loop ot the coil produces a magnetic field = Bf.
By increasing the number of loops in a coil the magentic field per loop is addidive.
So The B magnetic field for n loops would be equal to = n x Bf.
The ratio of the magnetic force to the square of the moving electron charge per unit time in the circuit is a constant called Mu sub o.
2007-09-03 01:52:39 · answer #1 · answered by goring 6 · 0⤊ 0⤋
the greater number of coils cut by the magnetic field, the greater the induced voltage.
2007-09-03 01:16:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
increase in the number of turns increases the sudden change in magnetic field and hence increases the potential difference................purely by lenz law
2007-09-03 01:39:34 · answer #3 · answered by shashank a 1 · 0⤊ 0⤋
they would probably be in same directions because since they are kept on the opposite sides therefore if the one on the left hand side deflects towards east then the one on the right would be facing towards its east ..................
2016-05-20 00:32:29 · answer #4 · answered by shannan 3 · 0⤊ 0⤋