How could I find the x -intercept, y -intercept and slope of the graph of 2x–3y+6=0?

Answer 1

rearrange the equation 3y = 2x + 6
y = 2/3 x + 2

slope = 2/3

x intercept is when y = 0

2x + 6 = 0 2x = -6 x = -3

y intercept is when x = 0
-3y + 6 = 0 3y = 6 y = 2

Answer 2

First, arrange the equation in the following order,
y = mx + b
where m = the slope ; b = y-intercept

2x - 3y + 6 = 0
-3y = -2x - 6
y = 2/3x + 2

From the equation above,
Slope = 2/3 ;
y-intercept = 2

To find x-intercept, y must be 0
0 = 2/3x + 2
2/3 x = -2
x = [ -2 / (2/3) ]
x = -3
Therefore, x-intercept = -3

Answer 3

To find the x intercept, set y=0 and solve for x. To find the y intercept, set x=0 and solve for y. To find the slope of the equation, rearrange the equation so you get y=f(x). The coefficient of x is the slope of the line.

Answer 4

For slope, solve the equation to look like this:

y=mx+b

Whatever value m is, that is your slope.

(If you have calculus...which I am guessing not, you can take the derivative with respect to x also.)

For the x intercept (where this line intercepts the x-axis), make the value for y = 0.

For the y intercept (where this line intercepts the y-axis), make the value for x = 0.

Answer 5

2x – 3y + 6 = 0
3y = 2x + 6
y = 2/3x + 2

y-int is 2
slope is 2/3

0 = 2/3x + 2
2/3x = -2
x = -3 (x-int)

Answer 6

First calculate for y by making x=0
Then calculate for x by making y=0

Thus, when x=0, y must be 2.
and, when y=0, x must be -3

Now graph it.