when a ball is thrown straight upward in the absence of air resistance, by how does the speed decrease each second?
after it reaches the top and begins its return downward, by how much does it speed increase each second?
how much time is required in going up compared to coming down?
2007-09-02 17:36:30 · 6 answers · asked by stop global warming!!! 1 in Science & Mathematics ➔ Physics
All the time the only force on the ball is the force of gravity that produces the only acceleration of "g" (=9.8m/s^2) downward.
Thus when the ball is moving up its velocity gets reduced by 9.8 m/s in each second.
When the ball returns downward its velocity gets increased by 9.8 m/s in each second.
The time required for ascent is exactly equal to the time required for descent.
2007-09-02 17:47:12 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The speed decreases by 9.8m/s in each second.
After reaching the top in other words after is speed has decreased to zero, its speed begins to increase by 9.8m/s in each second.
The time of going up equals the time of coming down.
2007-09-02 18:08:43 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
Acceleration due to gravity is about 9.8m/s^2 or 32 ft/s^2.
The time the ball takes to reach the top should equal the time the ball takes to return to the point it was thrown up from.
2007-09-02 17:45:00 · answer #3 · answered by gudspeling 7 · 0⤊ 0⤋
The speed decreases by 9.8 m/s each second on Earth.
2007-09-02 17:50:04 · answer #4 · answered by gebobs 6 · 0⤊ 0⤋
It depends on the speed in which it originally was throm into the air and how long it was in the aire before started to descend.
2007-09-02 17:46:42 · answer #5 · answered by Unique 2 · 0⤊ 1⤋
acceleration due to gravity is 9.8 meters per second per second.
2007-09-02 17:44:53 · answer #6 · answered by Okino 3 · 0⤊ 0⤋