What is the acceleration of a rock at the top of its trajectory when thrown straight upward?

Question

Is it consistent with Newton's second law?

Answer 1

It depends on the forces acting on the rock, generally gravity and drag. Drag is often ignored and gravity approximated to the mass of the rock times a constant acceleration of -9.8 m/s^2. Ignoring drag and keeping acceleration constant simplifies the problem.

And, yes it obeys Newton's second law. At least it mostly does. Technically there are relativistic effects on the rock, but they can be ignored, especially since the velocity right at the peak of trajectory is 0.

Answer 2

The acceleration in any position as always g directed downwards and the force according to the second law is
F = m*g directed downwards
At the top the velocity is zero but the acceleration is constant

Answer 3

Remeber 1 thing...Laws are there for a reason..if they were violated by throwing a stone upwards then it wouldnt be called a Law and it wouldnt have been accepted for centuries...

and answer to ur question acceleration on any body on earth is always 9.8 m/s2 9read meter per second squared)...even u altough ur stationary..are pulled by earth and if u werent standing on anything ull be falling at 9.8 m/s2..

so whatever may be the case acc is always there and it it 9.8 m/s2..

Answer 4

lol the velocity of the rock is zero, the acceleration is minus one g assuming it is thrown up on the earths surface.
i think is -32.2 feet per second per second
trick question...luv it...

yes, is the 'force' of gravity acting on the object which is changing its velocity (speed/ direction)
the actual force is -mg or massxgravity acceleration
lol this the simple answer...

Answer 5

Zero.

Answer 6

yes.