A flat circle of radius 18 cm is placed in a uniform electric field of magnitude 5.1x10^2 N/C.
b) What is the electric flux through the circle when its face is at 40° to the field lines?
Equation:
=EA cos ()
E=5.1x10^2
A=pi x .18^2 = .102
angle=40 degrees
(5.1x10^2)(.102)(cos 40)
=39.84
Yet it is wrong. What am I doing wrong?
2007-09-02 14:15:17 · 2 answers · asked by Jessie L 2 in Science & Mathematics ➔ Physics
The normal component is Esin 40º
so
flux = EA sin 40ª = and you
have to take meters for the area to have coherent units
2007-09-02 14:25:48 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
first you must convert to meter unit by dividing 18cm by factor 100 so 0.18
so A= pi X 0.18*2 = .101
substitute the angle equal 50 degree
2007-09-02 18:24:40 · answer #2 · answered by MOHAMMAD A 1 · 0⤊ 0⤋