A boy runs 30 m east , 40 m north, 50 m west. What is his net displacement? can you please explain how you did it?
2007-09-02 14:11:53 · 3 answers · asked by pinkduck000 2 in Science & Mathematics ➔ Physics
Hmmm ...
30 m east , 40 m north, 50 m west....
Displacement is a vector that has a magnitude (D) and an angle A.
D=sqrt( X^2 + Y2)
D=sqrt(50-30)^2+40^2)= 44.7 m North West
The angle A= arcTan( dy/dx)=
A= arcTan(40/20)= 63.4 deg from western axis ( conventional negative x-axix)
2007-09-02 14:29:31 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
The net displacement is 40 north and 20 west of the starting position. Displacement is simply the difference in starting and ending positions in some number of dimensions, in this case, 2 dimensions. All you need do is draw a diagram...
2007-09-02 14:22:17 · answer #2 · answered by rowlfe 7 · 0⤊ 0⤋
Call ABCD the points where the boy started ,changes or ended
This points form a trapeze and you need AD .
You can form a right angle triangle with none side 40m(a leg and the other leg (50-30)=20m
The net displacement AD = sqrt( 1600+400)=20*sqrt(5)
2007-09-02 14:35:02 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋