How do you find the value of --> sin18 deg 10' ?

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How do you find the value of --> sin18 deg 10' ?

I'm not sure how to work sine, cosine, and tangent problems that have minutes (eg. 10' from the above question). Help would be much appreciated. Thanks.

2007-09-02 14:11:23 · 2 answers · asked by Lovelylady 3 1 in Science & Mathematics ➔ Mathematics

2 answers

First converts minutes, and if nececcary seconds to degrees.

18°10' = 18 10/60°

Now take the sine.

sin(18°10') = sin(18 10/60°) ≈ sin(18.1666667°) ≈ 0.3117821

2007-09-02 14:17:08 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋

chnage it to degrees in decimal
18 deg 10' = 18 + 10/60
= 18.1667 deg
then calculator in degree mode will give sin(18.1667)

2007-09-02 21:17:08 · answer #2 · answered by vlee1225 6 · 0⤊ 0⤋