determine the solutions for polynomial 4x^5-8x^4=0?

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determine the solutions for polynomial 4x^5-8x^4=0?

2007-09-02 14:01:32 · 3 answers · asked by yung one 1 in Science & Mathematics ➔ Mathematics

3 answers

4x^5-8x^4=0?
= 4x^4(x-2) = 0
Let 4x^4=0
. . .x^4 = 0/4 = 0 or x=0
Let(x-2) = 0
. . .x = 2
Hence, the values of x are 0 or 2. . . Ans.
. . . . . . ===================

2007-09-02 14:48:44 · answer #1 · answered by Joymash 6 · 0⤊ 0⤋

Factor it to solve for x.

4x^5 - 8x^4 = 0
4x^4(x - 2) = 0

x = 0, 2

2007-09-02 21:04:29 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋

4x^4(x - 2) = 0

x = 0, x = 2

2007-09-02 21:05:15 · answer #3 · answered by Anonymous · 0⤊ 0⤋