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3 answers

If f(x) = x^a
f'(x) = a*x^(a-1)

f(x) = 13/(x^11)
f(x) = 13*x^(-11)
f'(x) = 13*(-11)*x^(-11-1)
f'(x) = -143*x^(-12)
f'(x) = -143/(x^12)

2007-09-02 13:41:50 · answer #1 · answered by gudspeling 7 · 0 0

dy/dx = 13 * (x^11)^-1

=13 * x^-11

= 0 + 13(-11x^-12)

=-143/(x^12)

2007-09-02 20:52:14 · answer #2 · answered by de4th 4 · 0 0

13/(x^11)
=13x^-11
dy/dx = -11*13x^-12
= -143/x^12

2007-09-02 20:47:44 · answer #3 · answered by ironduke8159 7 · 0 0

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