I Need help with my college algebra math word problem!?

Question

A chemist has a 35% saline solution and a 60% saline solution available. How many milliliters of each of these available solutions should she mix to obtain 700 mL of a 40% solution?

Answer 1

Let him be required to mix x ml of the 35% solution with 700-x ml of 60% solution to get 700 ml of 40% solution
According to the problem,
0.35x+0.60(700-x)=0.40*700
or,0.35x+420-0.60x=280
or,-0.25x=280-420= -140
or x= -140/-0.25=560
Therefore he should nix 560 ml of 35% solution with (700-560) or 140 ml of 60% solution

Answer 2

x = amount of 35%
700-x = amount of 60%
.35x + .6(700-x) = .4*700
.35x + 420 -.6x = 280
-.25x = - 140
x = 560 ml of 35%
700 -x = 140 ml of 60 %

Answer 3

permit x = variety quarters So 2x = style of dimes //// There are two times as many dimes as quarters & (2x+7) = style of nickels ///// There are seven extra nickels than dimes 5(2x+7) + 10(2x) + 25x = 310 10x +35 +20x +25x = 310 55x = 310 -35 55x = 275 x = 275/fifty 5 = 5 There are 5 quarters , 10 dimes & 27 nickels. permit v = velocity of freight practice Use d = vt so 225 = vt (a million) velocity of passenger practice is (v+14) mph so 295 = (v+14)t (2) 295 = vt + 14t 295 = 225 + 14t /// from (a million) vt =225 70 = 14t t = 70/14 = 5 hours practice speeds; Freight practice = d/t = 225/5 = 40 5 mph Passengar = 40 5 + 14 = fifty 9 mph Or do it this way 295/5 = fifty 9 mph

Answer 4

If she takes x ml of 35% and y ml of 60% solutions, we have

0.35 x + 0.6 y = 0.4 and x + y = 700

Solve them.

Answer 5

God i hate these, uhh i think it should be

.35x+.6y=.4
x+y=700

if you dont know how to solve those isolate one variable in an equation and then plug it into the other one and then solve for the variable then re-plug it into the original, i am 99% sure those are the right equations