http://tinypic.com/view.php?pic=66osbk3
ahh, please help. I have the worst headache from these problems. I can't get them to make any sense.
Thanks!
2007-09-02 12:32:19 · 4 answers · asked by Randy M 1 in Science & Mathematics ➔ Mathematics
x = 4sqrt(2)
x = 2*5 = 10
x =sqrt(2)/2*14 = 7sqrt(2)
x = 6sqrt(3)
2007-09-02 12:40:33 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
1. x = 4 sec 45deg = 4sqrt2 = 5.656
2. x = 5 sec 60deg = 5(2) = 10
3. x = 14 sin 45deg = 14/sqrt2 = 9.898
4. it is equilateral triangle whose height is
x = side(sqrt3)/2 = (12/2)sqrt3 = 10.392
2007-09-02 19:50:18 · answer #2 · answered by sv 7 · 0⤊ 0⤋
the special triangle is right angle triangle
1. use the relationship of Sine, Cosine Tangent of right angle triangles to help you.
2. also the a^2 =b^2+ c^2
2007-09-02 20:01:57 · answer #3 · answered by herbman76 2 · 0⤊ 0⤋
do ur own homework.
2007-09-02 19:39:20 · answer #4 · answered by equineabi 2 · 1⤊ 0⤋