Can you help me with algebra 1?

Question

Here is my homework questions,please help...
1. 2x²- 5x = 0
2. 3x² - 2x = 1
3. 2x² - x-15 = 0
4. t² - t- 6 = 0
5. 12x² - x - 6 = 0
6. m² + 12m +11m = 0
Please help me, I am so confused, and I'll give you best answer, if you get it right!

Can someone at least do one, please? I can't do those ones.

oh ya, I forgot. haha, it is factoring.

Answer 1

2x^2-5x=0
factor out the x so it becomes
x(2x-5)=0
x= 0, 5/2

get it? do it to number 2

for 3 4 5 6 use quadratic formula -b +/- square root of b^2 -4ac

Answer 2

factorize

1. x(2x-5)=0 x = 0 or 2x-5 = 0 x = 5/2
2. 3x² - 2x - 1 = 0 (3x+1)(x-1)=0 x=1 or x=-1/3
3. 2x² - x-15 = 0 (2x+5)(x-3)=0 x=3 or x=-5/2
4. t² - t- 6 = 0 (t-3)(t+2) = 0 t=3 or t=-2
5.12x² - x - 6 -0 (3x+2)(4x-3)=0 x=3/4 or x = -2/3
6. m² + 12m +11m = 0 (m+11)(m+1)=0 m = -11 or m=-1

Answer 3

1:
2x^2 - 5x = 0
x(2x - 5) = 0
Here we have two solutions: x = 0 or 2x-5 = 0.
2x - 5 = 0
2x = 5
x = 5/2
So x = 0 or 5/2.
2:
3x^2 - 2x = 1
3x^2 - 2x - 1 = 0
(x + 1)(3x - 1) = 0
Two solns: x+1 = 0 and 3x-1 = 0
x + 1 = 0
x = -1 (one answer)
3x - 1 = 0
3x = 1
x = 1/3 (other answer)
3: 2x^2 - x - 15 = 0
(2x + 5)(x - 3) = 0
2x + 5 = 0
2x = 5
x = 5/2 (one answer)
x - 3 = 0
x = 3 (other answer)
4: t^2 - t - 6 = 0
(t + 2)(t - 3) = 0
t + 2 = 0
t = -2 (one answer)
t - 3 = 0
t = 3 (other answer)
5: 12x^2 - x - 6 = 0
(4x - 3)(3x + 2) = 0
4x - 3 = 0
4x = 3
x = 3/4 (one ans)
3x + 2 = 0
3x = -2
x = -2/3 (other ans)
6: m^2 + 12m + 11m = 0
m^2 + 23m = 0
m(m + 23) = 0
m = 0 (one answer)
m + 23 = 0
m = -23 (other answer)

Answer 4

1. x=0; x=5/2
2. x=1; x= -1/3
3. x=3; x= -5/2
4. x=3; x= -2
5. x=3/4; x= -2/3
6. m= -1; m= -11

Assuming you want to find the values to make the equation equal...

Answer 5

1. x = 0
2. x = 1/7
3. x = 5
4. t = 2
5. x = 6/25
6. m = 24