someone please help me solve these problems!
1.) Arctan( - root 3 over 3)
2.) sin ( sin -1 3/8)
by -1 i mean the little inverse sign
2007-09-02 09:50:28 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
instead of just giving answers, could you explain how to get the answer???
thanks.
2007-09-02 10:02:04 · update #1
1) -π/6
2) sin ( arcsin ( 3/8 ) ) = 3/8
2007-09-02 09:56:49 · answer #1 · answered by Merlyn 7 · 0⤊ 0⤋
Arctan( - root 3 over 3) = -30 degress or -Pi/6
sin ( sin -1 3/8) is just 3/8 because the inverse of sine cancels sine
2007-09-02 10:00:00 · answer #2 · answered by Calculus 2 · 0⤊ 0⤋
The tangent is negative in the 2nd and 4th quadrants.Sqrt(3)/3 is the tangent of 30 degrees. So the the angle is either 150 degrees or 330 degrees.
sin(arcsin x) = x
Hence sin(arcsin 3/8) = 3/8
2007-09-02 10:15:04 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
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2016-11-14 00:29:28 · answer #4 · answered by vereen 4 · 0⤊ 0⤋