calculate the limit
2007-09-02 07:26:46 · 6 answers · asked by Deutschjoe 3 in Science & Mathematics ➔ Mathematics
1
Reason:
lim as x-->∞ 1/x = 0
So lim as x-->∞ e^(1/x) = e^0
e^0 = 1
2007-09-02 07:29:27 · answer #1 · answered by whitesox09 7 · 1⤊ 0⤋
Lim
e^1/x=
Lim 1/x=0
when x=unlimited
e^0=1
2007-09-02 14:38:05 · answer #2 · answered by koh_arian 2 · 0⤊ 0⤋
1
Basically we look at 1/x as x approaches infinity. As x gets bigger, 1/x will converge to 0 as 1/large number will be close to 0. So if we know the exponent is going towards 0, then e^0 = 1.
2007-09-02 14:32:55 · answer #3 · answered by Brandon R 2 · 0⤊ 0⤋
Since 1/x --> 0 as x --> infinity, e^(1/x) --> e^0 = 1
2007-09-02 14:33:30 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
Ok, as x goes to infinite, 1/x goes to zero.
From exponentiation your know that e^0 = 1
so the limit is 1.
Good luck!
2007-09-02 14:30:33 · answer #5 · answered by alrivera_1 4 · 0⤊ 0⤋
1/x goes to 0 as x goes to â
e^0 = 1
Lim xââ e^(1/x) = 1
2007-09-02 14:29:48 · answer #6 · answered by radne0 5 · 1⤊ 0⤋