Put all the 1-9 digits on each box, so that the total is 15 from every direction(vertical, horizontal and slope) when summed....
2007-09-02 05:05:37 · 4 answers · asked by Izati S 1 in Science & Mathematics ➔ Mathematics
This is one solution:
8 3 4
1 5 9
6 7 2
2007-09-02 05:11:32 · answer #1 · answered by Nelson_DeVon 7 · 0⤊ 0⤋
In 3x3 = 9 squares box digits 1 to 9 are to be put, one in each box the total being 15 horizontally, vertically and diagonally. For that 15/3 = 5 must occupy the central box and the remaining
1, 2, 3, 4, 6, 7, 8, 9 are to be in line with 5 in pairs making 10 like
1 and 9
2 and 8
3 and 7
4 and 6 and the rest is easy
2 9 4 I 4 3 8 I 8 1 6 I 6 7 2
7 5 3 I 9 5 1 I 3 5 7 I 1 5 9
6 1 8 I 2 7 6 I 4 9 2 I 8 3 4
2007-09-02 05:32:32 · answer #2 · answered by sv 7 · 0⤊ 0⤋
Magic square:
--6--1--8
--7--5--3
--2--9--4
Saludos.
2007-09-02 05:16:27 · answer #3 · answered by lou h 7 · 0⤊ 0⤋
If it is a box then surely it is 3D? The answers so far assume dimensions of 3x3x1 not 3x3. Just felt like being annoying....:)
2007-09-02 05:29:48 · answer #4 · answered by MeowRoar!!!! 2 · 0⤊ 0⤋